SOLUTION: Here are a few problems that I am grindin my teeth at: Factor completely: 3a^2 - 27b^2 would the answer be 3(a * a) - (3 * 3* 3)(b * b)? # 2 x^2 - 15wy + 3xy

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Question 43060: Here are a few problems that I am grindin my teeth at:
Factor completely:
3a^2 - 27b^2
would the answer be 3(a * a) - (3 * 3* 3)(b * b)?
# 2 x^2 - 15wy + 3xy - 5 wx
would it be (x8x) - (3*5wy) + 3xy - 5 wx?
# 3
9x^2 - 36y^2
would it be (3*3)(x*x) - 3*3*2*2(y*y)?
# 4
3x^2 + 2x - 8
would it be 5 (x*x + x) -8

Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website!
Factor completely:

factor out 3

both terms in paren are perfect squares, ,
so, use the rule that
answer
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this is a tough one. The best I can come up with is this

factor out (x + 3y)
answer, but I'm not sure
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both terms are perfect squares, ,
answer
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this is not hard, just have to puzzle it out
The factors of are 3x and x
(3x - ?)(x + ?)
I tried
(3x - 2)(x + 4)
that equals
wrong
then
(3x - 4)(x + 2) BINGO answer

SOLUTION: Here are a few problems that I am grindin my teeth at: Factor completely: 3a^2 - 27b^2 would the answer be 3(a * a) - (3 * 3* 3)(b * b)? # 2 x^2 - 15wy + 3xy - 5 wx woul