# SOLUTION: If one-half of one integer is subtracted from three-fifths of the next consecutive integer, the difference is 3. What are the two integers?

Algebra ->  Algebra  -> Polynomials-and-rational-expressions -> SOLUTION: If one-half of one integer is subtracted from three-fifths of the next consecutive integer, the difference is 3. What are the two integers?      Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Algebra: Polynomials, rational expressions and equations Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Polynomials-and-rational-expressions Question 42968: If one-half of one integer is subtracted from three-fifths of the next consecutive integer, the difference is 3. What are the two integers?Answer by jmg(22)   (Show Source): You can put this solution on YOUR website!It talks about an integer and the next consecutive integer So you would let the integer be n, and the next consective would be 1 more than that number so it would be (n+1) Using the question: If one-half of one integer is SUBTRACTED FROM three-fifths of the next, the difference is 3. Just change the words to numbers and symbols. 1/2(n) is SUBTRACTED FROM 3/5(n+1) = 3 , so you would actually write it 3/5(n + 1) - 1/2(n) = 3 Distribute 3/5(n) + 3/5 - 1/2(n) = 3 Combine your like terms the 3/5 and 1/2 n 1/10(n) + 3/5 = 3 Move the 3/5 to the other side 1/10(n) = 12/5 Multiply by the reciprocal of 1/10, which would be 10/1 in order to eliminate the fraction in front of the n. This gives you n = 24, which is the integer, so the next consecutive integer would be 24 + 1 = 25. So your numbers are 24 and 25 Hope this helps