SOLUTION: I need help could someone please explain this to me? the equation of the line that is perpendicular to the graph of y=1/3x-4; passing through (0,-1)

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Question 427670: I need help could someone please explain this to me?
the equation of the line that is perpendicular to the graph of y=1/3x-4; passing through (0,-1)

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
Using the standard slope-intercept form for an equation of a line y = mx + b
where m is the slope and b the y-intercept.
y=1/3x-4 |Slope m = (1/3) AND the slope of a line perpendicular to it is -3/1
Perpendicular Lines have slopes that are negative reciproclas of one another.
New Line:
y = -3x + b |using Pt(0,1) to solve for b
1 = -3*0 + b
1 = b EQ of this line is y = -3x+1


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