SOLUTION: <pre>Multiply 2x² - x - 3 3x² - 11x - 20 ——————————————— × ———————————————— 3x² + 7x + 4 4x² - 9</pre>

Algebra.Com
Question 42339:
Multiply 

  2x² - x - 3      3x² - 11x - 20
——————————————— × ————————————————
 3x² + 7x + 4        4x² - 9

Answer by AnlytcPhil(1806)   (Show Source): You can put this solution on YOUR website!
Multiply 

  2x² - x - 3      3x² - 11x - 20
——————————————— × ————————————————
 3x² + 7x + 4        4x² - 9

Factor both numerators and both 
denominators:

 (x + 1)(2x - 3)      (x - 5)(3x + 4)
————————————————— × ———————————————————
 (x + 1)(3x + 4)      (2x - 3)(2x + 3)
 
Indicate the multiplication of the 
numerators and denominators all as one
fraction:

 (x + 1)(2x - 3)(x - 5)(3x + 4)
—————————————————————————————————
 (x + 1)(3x + 4)(2x - 3)(2x + 3)

Cancel the (x + 1)'s, the (2x - 3)'s,
and the (3x + 4)'s

    1       1              1
 (x + 1)(2x - 3)(x - 5)(3x + 4)
—————————————————————————————————
 (x + 1)(3x + 4)(2x - 3)(2x + 3)
    1       1       1

So we end up with

 x - 5
————————
 2x + 3

Edwin
AnlytcPhil@aol.com

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