SOLUTION: factor the polynomial completely 27a^3-8b^3

Question 420370: factor the polynomial completely
27a^3-8b^3
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
factor the polynomial completely
27a^3-8b^3
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difference of cubes
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= (3a-2b)[(3a)^2+(3a)(2b)+(2b)^2]
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= (3a-2b)(9a^2 + 6ab + 4b^2)
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Cheers,
Stan H.
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