SOLUTION: 5n^2+19n+12
2v^2+11v+5
2n^2+5n+2
m^+2m-24
x^2-4x+24
k^2-13k+40
Algebra.Com
Question 420164: 5n^2+19n+12
2v^2+11v+5
2n^2+5n+2
m^+2m-24
x^2-4x+24
k^2-13k+40
Answer by dnanos(83) (Show Source): You can put this solution on YOUR website!
= multiply 5*12=60...Search among the factors of 60 to find two of them having sum 19 ( that is...4*15=60 4+15=19)
after that we have:
=
=
etc.....
Same way:
= We have 2*5=10 1*10=10 1+10=11
=
=
For a better way we use the of the general formula and if we find then we cannot factorize.
I.e.the above:
a=1,b=-4,c=24
and
RELATED QUESTIONS
5n^2+19n+12 (answered by stanbon)
3p^2-2p-5
2n^2+3n-9
3n^2-8n+4
5n^2+19+12
2v^2+11v+5
2n^2+5n+2... (answered by checkley77)
Factor... (answered by lynnlo)
5n^2 - 20 m^2+4p
--------- x --------- = ?
m+2p (answered by Edwin McCravy)
1/2(2n+6)=5n-12-n (answered by checkley77,Nieleya)
5n^2-30v+40 (answered by Alan3354)
-2(5n+1)=12 (answered by jim_thompson5910)
I'm working on factoring trinomials, and I cannot find the answer to two problems.
1. x... (answered by dfrazzetto)
5n^2-5n/3n-3 (answered by jim_thompson5910)