SOLUTION: The area of a square board is 4x2(squared)+56x+49. A)find an expression in terms of x for the perimeter of the board. B) find the perimeter when x=3

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: The area of a square board is 4x2(squared)+56x+49. A)find an expression in terms of x for the perimeter of the board. B) find the perimeter when x=3      Log On


   

Question 419045: The area of a square board is 4x2(squared)+56x+49. A)find an expression in terms of x for the perimeter of the board. B) find the perimeter when x=3
Answer by dnanos(83) About Me  (Show Source):
You can put this solution on YOUR website!
(A)~~~Area
%284x%29%5E2%2B56x%2B49=
%284x%29%5E2%2B2%2A4x%2A7%2B7%5E2=
%284x%2B7%29%5E2
The side of the square is: 4x+7
The perimeter is:
4(4x+7)=
16x+28
(B)~~~ when x=3
the perimeter is:
16x%2B28=16%2A3%2B28=48%2B28=76