SOLUTION: hi :)
how do i solve..
1. 2n^2+5n-42
2. 5x^2+35x+30
If you could help i would really appreciate it and thanks 4 your help! :)
Algebra.Com
Question 417682: hi :)
how do i solve..
1. 2n^2+5n-42
2. 5x^2+35x+30
If you could help i would really appreciate it and thanks 4 your help! :)
Found 2 solutions by sudhanshu_kmr, dnanos:
Answer by sudhanshu_kmr(1152) (Show Source): You can put this solution on YOUR website!
1. 2n^2+5n-42
= 2n^2+12n - 7n -42
= 2n(n+6) -7(n+6)
= (2n-7) (n+6)
2. 5x^2+35x+30
= 5x^2+30x+ 5x+30
= 5x(x+6) + 5(x+6)
= (5x+5)(x+6)
Answer by dnanos(83) (Show Source): You can put this solution on YOUR website!
We multiply
We try to find two numbers having sum 5 and product 84,that is
select from the factors of -84
-1*84
-2*42
-3*28
-4*21
-6*14
-7*12 etc.
Since -7+12=5 we stop here this search of number pairs and we have
=
=
=
For the other expression
=
1*6
2*3
3*2
etc.... stop... we found and
going back to the expression we obtain:
=
=
=