SOLUTION: Why is the followig incorrect? Give an example proving your answer... log[base 2](x+y)=log[base 2]x+log[base 2]y
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-> SOLUTION: Why is the followig incorrect? Give an example proving your answer... log[base 2](x+y)=log[base 2]x+log[base 2]y
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Question 415785
:
Why is the followig incorrect? Give an example proving your answer...
log[base 2](x+y)=log[base 2]x+log[base 2]y
Answer by
ewatrrr(24785)
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Hi
|Rule of Logarithims
DOES:
NO:
given: x = 1 and y =2 | log_2 (3)≠ log_2 (2) for example