Hi







  3^2 = (x+4)^2/9

  81= (x+4)^2

 ± 9 = x + 4

  -4 ± 9 = x   (x = -13 is an Extraneous solution)

   x = 5 

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
 2log[base 3](x+4)-log[base 3]9=2

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2log3(x+4) - log3(9) = 2

---

log3[(x+4)^2/9] = 2

----

(x+4)^2/9 = 3^2

(x+4)^2 = 81

---

x^2+8x+16-81 = 0

---

x^2 + 8x - 55 = 0

---

x  = [-8 +- sqrt(64-4*-55)]/2

----

x = [-8 +- sqrt(284)]/2

---

x = [-8 +- 2sqrt(71)]/2

---

x = -4+sqrt(71) or x = -4-sqrt(71)

==================

Cheers,

Stan H.

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