SOLUTION: 3x2-y2
for x=1/2
y=-1/3
Algebra.Com
Question 414384: 3x2-y2
for x=1/2
y=-1/3
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
I'm guessing that the 2's are exponents. If this is correct, please use the "^" character to indicate exponents:
3x^2-y^2
I'm also guessing the problem is to evaluate the expression when x = 1/2 and y = 1/3. To do this we just substitute the values for x and y and use the order of operations (aka PEMDAS) to simplify:
Note the use of parentheses. This is a good habit whenever you are substituting one expression for another.
Next, according to the order of operations we should exponentiate:
Next, multiply:
and last, subtract. Since these are fractions we need common denominators:
RELATED QUESTIONS
y=-2/3x2+3 (answered by Alan3354)
y = 3x2 + 2x 1 (answered by solver91311)
Evaluate this expression when x = 1/2 and y = 1/3
4x2+18xy2 -y2
(answered by MathLover1)
If x = 3 and y = -1, then 3x2 + 2xy 5 = ?" (answered by rfer,MathLover1)
(1/.5x+y โ 2y/.25x2+xy+y2)รท(.5x/.25x2โy2 +... (answered by ikleyn)
Find f(1) for f(x) = 4x3 - 3x2 - x + 2
(answered by jim_thompson5910)
how do I solve:
3x/5 = -6
y/4 + 2 = 7
16 = -2x/3
Find f(1) for f(x) = 2x3 (answered by RAY100)
Which of the following points is on the graph of the equation y = x2 ?
A. (-2, 4)
(answered by rfer)
Without expanding. Find the value of the determinant
|x y 1 (answered by Edwin McCravy)