SOLUTION: Do I leave my answer in fraction form or in whole number form? How do I know? x^2-3x-28=0 -3+-sqrt((3)^2-4(1)(-28))/(2(1)) -3+-sqrt(9+112)/(2) -3+-sqrt(121)/(2) x=(4)/(1)

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Question 411281: Do I leave my answer in fraction form or in whole number form? How do I know?
x^2-3x-28=0
-3+-sqrt((3)^2-4(1)(-28))/(2(1))
-3+-sqrt(9+112)/(2)
-3+-sqrt(121)/(2)
x=(4)/(1) and x=-(7)/(1)

Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Do I leave my answer in fraction form or in whole number form? How do I know?
x^2-3x-28=0
-3+-sqrt((3)^2-4(1)(-28))/(2(1))
-3+-sqrt(9+112)/(2)
-3+-sqrt(121)/(2)
x=(4)/(1) and x=-(7)/(1)
--------------------------------
Should be:
x = [-b +- sqrt(b^2-4ac)]/(2a)
---
x = [3 +- sqrt(9-4*1*-28)]/(2
---
x = [3 +- sqrt(121)]/2
---
x = [3+-11]/2
----
x = -8/2 or x = 14/2
---
x = -4 or x = 7
====================
Cheers,
Stan H.
===================

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:


Starting with the general quadratic





the general solution using the quadratic equation is:







So lets solve ( notice , , and )





Plug in a=1, b=-3, and c=-28




Negate -3 to get 3




Square -3 to get 9 (note: remember when you square -3, you must square the negative as well. This is because .)




Multiply to get




Combine like terms in the radicand (everything under the square root)




Simplify the square root (note: If you need help with simplifying the square root, check out this solver)




Multiply 2 and 1 to get 2


So now the expression breaks down into two parts


or


Lets look at the first part:





Add the terms in the numerator

Divide


So one answer is






Now lets look at the second part:





Subtract the terms in the numerator

Divide


So another answer is




So our solutions are:

or


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