SOLUTION: I am having trouble reducing the fraction within the quadratic equation. Would you please check my process to see if I did it right and help me with the ending part? (4x-3)^2=0

Algebra.Com
Question 411024: I am having trouble reducing the fraction within the quadratic equation. Would you please check my process to see if I did it right and help me with the ending part?
(4x-3)^2=0
(4x-3)(4x-3)=0
16x^2-12x-12x-9=0
16x^2-24x-9=0
-24+- sqrt((24)^2-4(16)(-9))/(2(16))
-24+- sqrt(576+576)/(32)
-24+- sqrt(1152)/(32)
-24+- sqrt(8(144))/(32)
-24+- sqrt(4(2)(144))/(32)
-24+- 12(2) sqrt(2)/(32)
-24+- 24 sqrt(2)/(32)
-1+- sqrt(3(1)/(3)

Found 2 solutions by edjones, ewatrrr:
Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
16x^2-24x+9=0 not -9
x=(24+-sqrt(576-4*16*9))/32 not -24
=(24+-sqrt(0))/32
=24/32
=3/4
.
Ed
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!


Hi

IF: 16x^2-24x-9=0  

THEN: 





[24 ± 24sqrt(2)]/(32)  = 3/4 ± (3/4)sqrt(2)



However, in this question: (4x-3)(4x-3)=0  | 16x^2-24x+9=0 



 x = 3/4 

 

RELATED QUESTIONS


Hi!
I am having trouble putting the following equation into proper form.  My assignment... (answered by jim_thompson5910)

x-8(3.14)=3.14 
This is what I have gotten for the equation above. Can you please see if  (answered by stanbon)

Hello! I have a word problem that I am having trouble with on my algebra homework... If... (answered by mananth)

I am having trouble figuring out how to work with the fractions.  Could you please... (answered by chitra,josmiceli)

I am having trouble with the following question:if the graph of a quadratic equation has... (answered by josgarithmetic,NR06)

Hello, I am having trouble with this one. Can you please breakdown in steps so I can see... (answered by stanbon,ankor@dixie-net.com)

I am having trouble solving the following problem. Please help.

seven thirds x = two... (answered by wuwei96815)

Hello!
I am having trouble with my homework and I would be very happy if someone could... (answered by Earlsdon)

one of the questions to my homewok that i am having trouble with answering was... (answered by josmiceli)