SOLUTION: Factor completely 9x^2 + 12xy + 4y^2 + 25

Algebra.Com
Question 41078: Factor completely
9x^2 + 12xy + 4y^2 + 25

Found 2 solutions by fractalier, stanbon:
Answer by fractalier(6550)   (Show Source): You can put this solution on YOUR website!
For
9x^2 + 12xy + 4y^2 + 25
I'm thinking it's supposed to be -25 at the end, but if this is correct, we have
9x^2 + 12xy + 4y^2 + 25 =
(3x + 2y)^2 + 25 =
(3x + 2y - 5i)(3x + 2y + 5i)

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
(9x^2 + 12xy + 4y^2) + 25
=(3x+2y)^2+5^2
=[3x+2y+5i][3x+2y-5i]
Cheers
Stan H.

RELATED QUESTIONS

factor completely... (answered by psbhowmick)
Factor the following completely: 9x^2 + 12xy + 4y^2 - 25 (answered by funmath)
Factor completely. 9x^2 + 12xy + 4y^2 -25 (answered by checkley75)
Factor Completely 9x^2 + 12xy + 4y^2 -... (answered by stanbon)
Factor Completely. 9x^2+12xy+4y^2-25.... (answered by jim_thompson5910)
factor completely... (answered by ramkikk66)
I am having problems with this problem. Factor completely. 9x^2 + 12xy + 4y^2... (answered by checkley71)
how can i factor this completely?... (answered by checkley75,Earlsdon)
Factor completely. I dont understand... (answered by stanbon)