SOLUTION: The length of a sign is 4 inches more than the width. The area is 45 square inches. Identify the length and the width of the sign.
Thank you
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-> SOLUTION: The length of a sign is 4 inches more than the width. The area is 45 square inches. Identify the length and the width of the sign.
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Question 41041: The length of a sign is 4 inches more than the width. The area is 45 square inches. Identify the length and the width of the sign.
Thank you Found 2 solutions by Nate, checkley71:Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website! I am going to guess that this sign is rectangular.
Length(l) = w + 4
Width(w) = w
Length * Width = Area
(w + 4)(w) = 45
w^2 + 4w = 45
w^2 + 4w - 45 = 0
(w + 9)(w - 5) = 0 or
Since the width can not be negative, your width is:
Plug:
Length = w + 4
Length = 5 + 4
Length = 9
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