Hi

Given the quadratic function f(x) = x^2 – 6x + 9, find a value of x such that f(x) = 25. 

f(x) = x^2 – 6x + 9

x^2 - 6x + 9 = 25

(x-3)^2 -9 + 9 = 25    |completing the square

 (x-3)^2 = 25

  (x-3) = ± 5

   x = 3 ± 5

  x = 8 and x = -2 



CHECKING our Answer(s)***

x^2 - 6x + 9 = 25

 64 - 48 + 9 = 25

 4 + 12 + 9 = 25

  

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!
 





Given the wording of the question, your answer is 100% correct.  I say this because the question asks: "...find a value of x...", and that is precisely what you did; the fact that there is another equally valid answer to the question, namely , notwithstanding.







John



My calculator said it, I believe it, that settles it



 

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