SOLUTION: Hi, I am solving by the quadradic formula -b sqrt (b^2-4ac)/(2a)
Would you show me how to finish this?
18x^2-39x+20=0
x = -39 sqrt (39)^2-4(18)(20)/(2(18))
x = -39 sqrt (15
Question 409229: Hi, I am solving by the quadradic formula -b sqrt (b^2-4ac)/(2a)
Would you show me how to finish this?
18x^2-39x+20=0
x = -39 sqrt (39)^2-4(18)(20)/(2(18))
x = -39 sqrt (1521 - 1440)/(36)
x = -39 sqrt (81)/(36)
x = (-39 - 9)/(36) lost here, what do I do? Answer by Edwin McCravy(20056) (Show Source): You can put this solution on YOUR website!
You have a sign wrong, and also you left out the "plus or minus", ±.
Here it is worked correctly step by step
Compare to
, ,
Using the +,
Using the -,
Edwin