SOLUTION: (20x^4-3x^3=11x^2-7x+12)�(4x-3) Write your answer in the form Q(x)+(R(x))/(4x-3) , where Q(x) is the quotient and R(x) is the remainder of the division. My answer shows thi

Question 408877: (20x^4-3x^3=11x^2-7x+12)�(4x-3)
Write your answer in the form Q(x)+(R(x))/(4x-3) , where Q(x) is the quotient and R(x) is the remainder of the division.
My answer shows this (20x^4-3x^3+11x^2-7x+12)/(4x-3)= this is blank + ?/4x-3
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!

       5x^3 +  3x^2 +  5x   +  2
      _______________________________
4x-3 /20x^4 -  3x^3 + 11x^2 - 7x + 12
      20x^4 - 15x^3
      -----------
              12x^2 + 11x^2
              12x^2 -  9x^2
              -------------
                      20x^2 -  7x
                      20x^2 - 15x
                      -----------
                               8x + 12
                               8x -  6
                               -------
                                    18

The remainder is 18 and the quotient is 5x^3 + 3x^2 + 5x + 2.

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