SOLUTION: A solution containing 30% insecticide is to be mixed with a solution containing 50% insecticide to make 200L of a solution containing 42% insecticide. How much of the 50% Insectici
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Question 40869: A solution containing 30% insecticide is to be mixed with a solution containing 50% insecticide to make 200L of a solution containing 42% insecticide. How much of the 50% Insecticide solutions should be used?
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A Chemist has one solution that is 60% chlorinated and another that is 40% chlorinated. How much of the first (60%) solution is needed to make a 100L solution that is 50% chlorinated?
Thanks soooo much!!!!!
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
I'll show you the first one...apply what I show you to the second one...here's the setup...
Let x be the amount of 30%. Thus 200-x is the amount of the 50%. Then we have
x(.30) + (200-x)(.50) = 200(.42)
.3x + 100 - .5x = 84
-.2x = -16
x = 80
200-x = 120
The second problem is almost exactly the same except for the numbers...
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