SOLUTION: Let width = w Area = {{{(length)*(width)}}} So {{{3x^2 + 5x = x*w}}} or {{{w = (3x^2 + 5x)/x = 3x + 5}}} So required width is (3x + 5).

SOLUTION: Let width = w Area = {{{(length)(width)}}} So {{{3x^2 + 5x = xw}}} or {{{w = (3x^2 + 5x)/x = 3x + 5}}} So required width is (3x + 5).

Question 40846: Let width = w
Area =
So
or
So required width is (3x + 5).
Answer by psbhowmick(878) (Show Source): You can put this solution on YOUR website!