SOLUTION: Hi, I finished this equation and would like to know if you would check my answer. My textbook answer is says 1 but I got 1 (1)(11). I would like to know how to do the problem cor

Question 408282: Hi, I finished this equation and would like to know if you would check my answer. My textbook answer is says 1 but I got 1 (1)(11). I would like to know how to do the problem correctly. Thanks.
(c+5)/(7)+(c-3)/(4)=(5)/(14)
common demoninator 28 and multiply by it.
28 (c+5)/(7)+ 28(c-3)/(4)= 28(5)/(14)
4c+5+7c-3=10
11c+2=10
-2 +2
(11c)/(11c)=12/11
c=1 (1)/(11)
Found 3 solutions by stanbon, josmiceli, solver91311:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
(c+5)/(7)+(c-3)/(4)=(5)/(14)
common demoninator 28 and multiply by it.
28 (c+5)/(7)+ 28(c-3)/(4)= 28(5)/(14)
-----
4(c+5) + 7(c-3) = 2*5
----
11c - 1 = 10
---
c = 1
===============
Cheers,
Stan H.

Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
You need a lot of help with fractions and multiplying factors
that are sums of quantities, for instance:
Suppose I break up one of these factors:
=
=
=

You need to go over this basic operation
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!

You have the right idea, but you misapplied the process of applying the common denominator. You need to review the Distributive Property:

John

My calculator said it, I believe it, that settles it

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