SOLUTION: Can someone please help, I am trying to help my child with algebra homework and I have no idea what I am doing on this problem. I do know A=L*W, but that is as far as I can remembe

Question 407816: Can someone please help, I am trying to help my child with algebra homework and I have no idea what I am doing on this problem. I do know A=L*W, but that is as far as I can remember with this stuff. Thank you.
The length of a rectangle is 2 meters more than it's width. If the area is 63 sq meters, what are the length and width?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The length of a rectangle is 2 meters more than it's width. If the area is 63 sq meters, what are the length and width?
------
Let the width be "x"
Then the length is "x+2"
---
A = LW
63 = (x+2)x
63 = x^2+2x
x^2 +2x - 63 = 0
----
Factor:
(x+9)(x-7) = 0
Positive solution:
x = 7 meters (width)
---
x+2 = 9 meters (length)
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Cheers,
Stan H.
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