Question 40731: 30/10+Y= 20/10-Y
Answer by tutorcecilia(2152)   (Show Source):
You can put this solution on YOUR website! 30/10+Y= 20/10-Y
This problem is asking you to solve for y. In order to solve for y, you must try to isolate the y to one side of the equation and all other terms to the other side of the equation.
This problem looks complicated, but it follows the same rules as:
a/b = c/x Solve for x
The quickest way to solve for x is to cross-multiply:
a/b = c/x
ax = bc
Divide both sides by "a"
ax/a = bc/a
x = bc/a
So, going back to your original problem, treat each term in the fractions as a, b, c, or x.
30/10+Y= 20/10-Y
First, cross-multiply:
30(10-y = 20(10+y)
Simplify using the distributive property will give you:
300 - 30y = 200 + 20y
Solve for "y". Remember, what you do to one side of the equation, you must do to the other side of the equation.
300 - 200 - 30y = 200 - 200 + 20y
100 - 30y = 20y
100 - 30 y + 30y = 20y + 30y
100 = 50y
100/50 = 50y/50
2 = y
Check to make sure this a true answer, by plugging "2" back into the orignial problem.
30/10+Y= 20/10-Y
30/10 + 2 = 20/10 - 2
30/12 = 20/8
2.5 = 2.5
The answer checks out!
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