Hi,

 x = 1 is a real root. Dividing by (x-1) to find the other two roots:

      3x^2 + 5x +6

      _______________________

x -1 | 3x^3+2x^2+x-6



(x-1)(3x^2 + 5x +6)= 0

     (3x^2 + 5x +6)= 0







the remaining two roots of 3x^3+2x^2+x-6 are complex roots.  

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