SOLUTION: college algebra - completing the square would you help me finish this? I wasn't sure what factors to pick out from 196 so I choose 4 times 49. How do I choose what to use? x^

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Question 405860: college algebra - completing the square
would you help me finish this? I wasn't sure what factors to pick out from 196 so I choose 4 times 49. How do I choose what to use?
x^2-10x+24=0
x=-10+-sqrt((-10)^2-4(1)(24))/2(1))
x=10 +- sqrt((100-(-96))/2)
x=10 +-sqrt((196)/(2)
2sqrt(4(49))/2))
sqrt(2^2(49))/(2)
2+-sqrt49/2
2(1+-sqrt49/2)
1sqrt49
x=1sqrt49 right?

Found 2 solutions by josmiceli, emargo19:
Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!

Here's how I do it:

Take 1/2 of the coefficient of , square it, and add it
to both sides.



Take the square root of both sides


and, also
(the other square root of 1)

from these, I get and , so
The factors are


Answer by emargo19(101)   (Show Source): You can put this solution on YOUR website!





and
and
and

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