SOLUTION: Hi I need to know how to solve this problem,please explain. 2b + 4b(2-b) , my answer is 4b-2b^2+8b-4b^2 I know is wrong now from here I have to subtract,but how that's where I

Question 404971: Hi I need to know how to solve this problem,please explain. 2b + 4b(2-b) , my answer is 4b-2b^2+8b-4b^2 I know is wrong now from here I have to subtract,but how that's where I am stuck. Thanks you!!!
Answer by IWork4Dessert(60) (Show Source): You can put this solution on YOUR website!
I'll start this problem from the beginning, just in case you made an error along the way.
2b+4b(2-b)
The first step is to distribute that 4b inside the parentheses, like so:
2b+8b-4b^2
I believe that's where you went wrong. I'm not entirely sure how you came up with the extra -2b^2 and how you got the 4b, but distribution is the proper way to start.
Next you need to combine your like terms. To add these numbers and variables together, they must have the same exponential value. You can't add 6b and 4b^2, as tempting as it may seem.
2b and 8b are like terms, so you add them.
10b-4b^2
That's your answer.
Hope this helps :)
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