SOLUTION: Good afternoon,.My problem is x3y2-3x2y2+6xy2-18y2 factor the expression completely this is what wrote; x3y2-3x2y2+6xy2-18y2=x(x2y2-3xy2)+6(xy2-3y2) this is as far as i got than

Question 402933: Good afternoon,.My problem is x3y2-3x2y2+6xy2-18y2 factor the expression completely this is what wrote;
x3y2-3x2y2+6xy2-18y2=x(x2y2-3xy2)+6(xy2-3y2) this is as far as i got than i got confused the book suggest to use a -1 so that a common binomial factor can appear.
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
y^2 is a common factor for all the terms

y^2(x^3 - 3x^2 + 6x - 18)

grouping ___ y^2[(x^3 - 3x^2) + (6x - 18)]

factoring ___ y^2{[x^2 (x - 3)] + [6 (x - 3)]}

rearranging ___ y^2 (x^2 + 6) (x - 3)
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