SOLUTION: Factor completely.
1. 6x^6 + 8x^4 – 15x^3 – 20x
2. 9x^2 – 27x + 20
3. 2x^2 – 128
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Question 401301: Factor completely.
1. 6x^6 + 8x^4 – 15x^3 – 20x
2. 9x^2 – 27x + 20
3. 2x^2 – 128
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Factor completely.
1. 6x^6 + 8x^4 – 15x^3 – 20x
2. 9x^2 – 27x + 20
3. 2x^2 – 128
1. 6x^6 + 8x^4 – 15x^3 – 20x
=2x^4(3x^2+4)-5x(3X^2+4)
=(3x^2+4)(2x^4-5x)
=(3x^2+4)(2x^3-5)(x)
2. 9x^2 – 27x + 20 (set to zero and solve quadratic equation)
=(3x=5)(3x-4)
3. 2x^2 – 128
=x^2=128/2
=x^2-64 (difference of squares)
=(x+8)(x-8)
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