A jar of dimes and quarters contains $15.25. There are 103 coins in all. How many quarters in the jar? thanx Let D = the number of dimes and Q be the number of quarters >>...There are 103 coins in all...<< Therefore D + Q = 103 >>...A jar of dimes and quarters contains $15.25...<< The money which the D dimes is worth is $.10 times D or .10D The money which the Q quarters is worth is $.25 times Q or .25D So .10D + .25D = 15.25 We have this system: D + Q = 103 .10D + .25D = 15.25 Can you solve that system? If not post again. Answer 70 dimes and 33 quarters Edwin McCravy AnlytcPhil@aol.com