SOLUTION: Find 4 consecutive odd integers if the product of the two smaller integers is 112 less than the product of the two larger integers. thanx

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Question 40005: Find 4 consecutive odd integers if the product of the two smaller integers is 112 less than the product of the two larger integers.
thanx
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
let smallest number be x.
Then we have x+2, x+4 and x+6 successively.

So, x(x+2) = (x+4)(x+6) - 112
+x%5E2%2B2x+=+x%5E2+%2B+10x+%2B+24+-+112+
+x%5E2%2B2x+=+x%5E2+%2B+10x+-+88+
+2x+=+10x+-+88+
+-8x+=+-+88+
x = (-88)/(-8)
x = 11

so, we have 11,13,15 and 17

CHECK:
11*13 is 143
15*17 is 255

and 255-143 is 112: correct

jon.