SOLUTION: The sum of the squares of two consecutive negative integers is 61. Find the smaller of the two integers.

Question 399916: The sum of the squares of two consecutive negative integers is 61. Find the smaller of the two integers.
Found 2 solutions by Alan3354, Tatiana_Stebko:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
61/2 = 30.5
sqrt(30.5) =~ 5.5, the middle
--> 5 & 6
Also -6 & -5

Answer by Tatiana_Stebko(1539) (Show Source): You can put this solution on YOUR website!
If the first integer is x, then the second is (x+1)(because they are the two consecutive integers)
the sun of their squares is
From problem's text the sun of their squares is 61,
so we have equation:

(formula , so

or
or
extraneous root because in problem negative integers
So x=-6 is the first integer
the second is (x+1)=-6+1=-5
Answer: The smaller integer is -6
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