SOLUTION: How do I find the difference? (6x^2-3x-9)-(-2x^2+8x+3)
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Question 399464
:
How do I find the difference?
(6x^2-3x-9)-(-2x^2+8x+3)
Found 2 solutions by
ewatrrr, Jazzqueen
:
Answer by
ewatrrr(24785)
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Hi
Simplifying
(6x^2-3x-9)-(-2x^2+8x+3)
6x^2-3x-9 + 2x^2-8x-3
8x^2 - 11x - 12
Answer by
Jazzqueen(1)
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(6x^2-3x-9)-(-2x^2+8x+3)
6x^2-3x-9+2x^2-8x-3
6x^2-3x-9
2x^2-8x-3
8x^2-11x-12
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