SOLUTION: Simplify: 5x^4 over 8 x^2 y^2 * 8y^5 over 15 I got x^4 8 y^3 over 8 x^2 3

Algebra.Com
Question 398284: Simplify: 5x^4 over 8 x^2 y^2 * 8y^5 over 15
I got x^4 8 y^3 over 8 x^2 3

Answer by jsmallt9(3758)   (Show Source): You can put this solution on YOUR website!

When multiplying fractions not only is it OK to cancel common factors between the numerator and denominator (even from one fraction across to the other), it is a good idea. So I will start by factoring the numerators and denominators in a way that should make the common factors obvious:

Now we can cancel the common factors:

which simplifies to:

which is very easy to multiply:


RELATED QUESTIONS

Which one of these are linear equations? x-6y=8 y=-1 y=x^2+4 5 over x+3 over... (answered by algebrahouse.com)
how do i simplify fractional equations involving variables and exponents such as 2x+8... (answered by ReadingBoosters)
x+2 over x-8= 4 over... (answered by jim_thompson5910)
X+3 OVER 4= X OVER... (answered by Fombitz)
OMG- ready to tear out my hair! Please help. x-(8-5x)= 11(x-1) 3x +2 =8x -4 (I got (answered by jim_thompson5910,MathLover1)
Can you walk me through equations like this? (X-5 over 5)+ (x over 4)=8 (5-2X over... (answered by stanbon)
x + 4 over 8 = 3 over... (answered by edjones)
x-1 over 8 = 5 over... (answered by ewatrrr)
complex fractions 9x^2 - 16y^2 over xy all over 3 over y - 4 over... (answered by gsmani_iyer)