Hi

y = 12x^3-12x

Finding the zeros of the function

  12x^3 - 12x = 0

  12x(x^2 - 1) = 0

  12x(x+1)(x-1)= 0



  12x = 0   x = 0

  (x+1)=0   x = -1

  (x-1)= 0  x = 1 

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