SOLUTION: Jack usually mows his lawn in 3 hours. Marilyn can mow the same yard in 7 hours. How much time would it take for them to mow the lawn together?

Algebra.Com
Question 395319: Jack usually mows his lawn in 3 hours. Marilyn can mow the same yard in 7 hours. How much time would it take for them to mow the lawn together?
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
Let x represent time to mow the lawn together
Question states***per hour being the equalizer
1/3 + 1/7 = 1/x |Multiplying each term by 21x so as alll denominators=1
7x + 3x = 21
10x = 21 hr
x = 2.1 hr
RELATED QUESTIONS

Jack usually mows his lawn in 7 hours. Marilyn can mow the same yard in 5 hours. How much (answered by dabanfield,Alan3354)
Jack usually mows his lawn in 5 hours. Marilyn can mow the same yard in 4 hours. How much (answered by mananth)
jack usually mows his lawn in 3 hours. Marilyn can mow the same yard in 7 hours. How much (answered by scott8148)
Please help me Jack usually mows his lawn in 3 hours. Marilyn can mow the same yard in (answered by ewatrrr)
Jack usually mows his lawn in 6 hours. Marilyn can mow the same yard in 3 hours. How much (answered by checkley77)
Jack usually mows his lawn in 3 hours. Marilyn can mow the same yard in 4 hours. How much (answered by solver91311)
Jack usually mows his lawn in 3 hours. Marilyn can mow the same yard in 5 hours. How much (answered by stanbon,CharlesG2)
Jack usually mows his lawn in 5 hours. Marilyn can mow the same yard in 3 hours. How much (answered by josmiceli)
Jack usually mows his lawn in 7 hours. Marilyn can mow the same yard in 6 hours. How... (answered by jorel1380)