SOLUTION: factor 8b^2+24b+18

Question 392588: factor 8b^2+24b+18
Answer by haileytucki(390) (Show Source): You can put this solution on YOUR website!
8b^(2)+24b+18
Factor out the GCF of 2 from each term in the polynomial.
2(4b^(2))+2(12b)+2(9)
Factor out the GCF of 2 from 8b^(2)+24b+18.
2(4b^(2)+12b+9)
In this problem (3)/(2)*(3)/(2)=9 and (3)/(2)+(3)/(2)=12, so insert (3)/(2) as the right hand term of one factor and (3)/(2) as the right-hand term of the other factor.
2(b+(3)/(2))(b+(3)/(2))
Remove the fraction by multiplying the first term of the factor by the denominator of the second term.
2(2b+3)(2b+3)
Combine the two common factors of (2b+3) by adding the exponents.
2(2b+3)^(2)
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