SOLUTION: 2(x-3y)^2 + 4x(x-3y)=

Question 391185: 2(x-3y)^2 + 4x(x-3y)=
Answer by haileytucki(390) (Show Source): You can put this solution on YOUR website!
2(x-3y)^(2)+4x(x-3y)
Squaring an expression is the same as multiplying the expression by itself 2 times.
(2*(x-3y)(x-3y))+4x(x-3y)
Multiply each term in the first group by each term in the second group using the FOIL method. FOIL stands for First Outer Inner Last, and is a method of multiplying two binomials. First, multiply the first two terms in each binomial group. Next, multiply the outer terms in each group, followed by the inner terms. Finally, multiply the last two terms in each group.
(2(x*x+x*-3y-3y*x-3y*-3y))+4x(x-3y)
Simplify the FOIL expression by multiplying and combining all like terms.
(2(x^(2)-6xy+9y^(2)))+4x(x-3y)
Multiply 2 by each term inside the parentheses.
(2x^(2)-12xy+18y^(2))+4x(x-3y)
Multiply 4x by each term inside the parentheses.
(2x^(2)-12xy+18y^(2))+4x^(2)-12xy
Since 2x^(2) and 4x^(2) are like terms, add 4x^(2) to 2x^(2) to get 6x^(2).
6x^(2)-12xy+18y^(2)-12xy
Since -12xy and -12xy are like terms, subtract 12xy from -12xy to get -24xy.
6x^(2)-24xy+18y^(2)
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