SOLUTION: 1.) 8-2x / 5x+10 = blank / 5y(x+2) 2.) 3x^2+10x+3 / x-1 = x(x+3)(x+5)(3x+1) / blank What is in the blank? Thank you.

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Question 390525: 1.) 8-2x / 5x+10 = blank / 5y(x+2)
2.) 3x^2+10x+3 / x-1 = x(x+3)(x+5)(3x+1) / blank


What is in the blank? Thank you.

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi,
The 'blank' is used for the request to place in it an appropriate response:
For ex: 8-2x / 5x+10 = blank / 5y(x+2)
'performing operations on left side of equal sign to reach the right side denominator'
8-2x / 5x+10 |Simplifying
2(4-x) / 5(x+2) |Multiplying both numerator and denominator by y
2y(4-x) / 5y(x+2) | One would put 2y(4-x) in the 'blank' for the numerator
ex: 3x^2+10x+3 / x-1 = 3x^2+10x+3 / x-1 = x(x+3)(x+5)(3x+1) / blank
'performing operations on left side of equal sign to reach the right side numerator'
3x^2+10x+3 / x-1 |factoring the numerator
(3x + 1)(x+3) /(x-1) |Multiplying numerator and denominator by x(x+5)
(3x + 1)(x+3)x(x+5) /(x-1)x(x+5) OR x(x+3)(x+5)(3x + 1) /x(x-1)(x+5)
One would put x(x-1)(x+5) in the blank for the denominator
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