SOLUTION: (3x)/(x^2+2x-8)=(1/(x-2))+(x/(x+4))

Question 390360: (3x)/(x^2+2x-8)=(1/(x-2))+(x/(x+4))
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(3x)/(x^2+2x-8)=(1/(x-2))+(x/(x+4))
-----
(3x)/[(x+4)(x-2)] = [(x+4+x(x-2)]/[(x-2)(x+4)]
----
Multiply thru by (x-2)(x+4) to get:
3x = x+4 + x^2-2x
---
3x = x^2-x+4
---
x^2-4x+4 = 0
----
Factor to get:
(x-2)^2 = 9
---
Solution x = 2
---
But x cannot be 2 because (x-2) is one of the denominators
of the original problem.
----
Conclusion:
No solution
===============
Cheers,
Stan H.
=======

RELATED QUESTIONS
4(x-1)+2=3x+8-2x (answered by jim_thompson5910)

4(x-1)+2=3x+8-2x (answered by sailajasrinivasp)

Solve for x... (answered by jim_thompson5910)

Solve for X 4(x � 1) + 2 = 3x + 8 �... (answered by jim_thompson5910)

3x+6/ x^2+3x+2*x+1/2x+8 (answered by Alan3354)

solve... (answered by mananth)

The fraction x�+2x-8/x-2 is equivalent to (1)3x+4 (2)(x-4)(x+2)/(x-2) (3)x-4 (4)x+4 (answered by jim_thompson5910)

2x+4 / x+1 + 3 / x + 6 / x^2 +... (answered by Tatiana_Stebko)

(x-2)(2x-4)-(x-2)(3x+4)/ (2-x)(x+8) = (answered by Edwin McCravy)