SOLUTION: What would the polynomial with real coefficients whose zeroes are -4, 1-i, and 1 + i be?

Question 389745: What would the polynomial with real coefficients whose zeroes are -4, 1-i, and 1 + i be?
Found 2 solutions by stanbon, scott8148:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
What would the polynomial with real coefficients
whose zeroes are -4, 1-i, and 1 + i be?
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f(x) = (x+4)(x-(1-i))(x-(1+i))
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f(x) = (x+4)((x-1)+i)((x-1)-i)
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f(x) = (x+4)((x-1)^2+1)
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f(x) = (x+4)(x^2-2x+2)
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f(x) = x^3+2x^2-4x+8
===========================
Cheers,
stan H.

Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
if r is a root , a zero , then (x - r) is a factor

multiply the three factors together to find the polynomial ___ (x + 4)(x - 1 + i)(x - 1 - i)
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