# SOLUTION: word problem. please use a table and the 5 step method to solve this problem. thank you. marcus invested a sum of money at 5%. he invested an amount of money \$250 more than the

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: word problem. please use a table and the 5 step method to solve this problem. thank you. marcus invested a sum of money at 5%. he invested an amount of money \$250 more than the       Log On

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 Click here to see ALL problems on Polynomials-and-rational-expressions Question 389727: word problem. please use a table and the 5 step method to solve this problem. thank you. marcus invested a sum of money at 5%. he invested an amount of money \$250 more than the first amount at 6%. if the annual income from both investments totaled \$59, how much did he invest at each rate. Answer by ewatrrr(11176)   (Show Source): You can put this solution on YOUR website! Hi, Let x represent the first amount invested at 5% Therefore, (x+ \$250) would be the amount invested at 6% question States*** .05x + .06(x + \$250) = \$59 solving for x .05x + .06x + .06*\$250 = %59 .11x = \$59 - .06*\$250 .11x = \$59 - \$15 .11x = \$44 x = \$44/.11 = \$400, amount invested at 5% the amount invested at 6% would be \$650 (\$400+ \$250) IV. CHECKING Our Answer*** .05*\$400 + .06*\$650 = \$20 + \$39 = \$59