# SOLUTION: 3y+2/7ythird divide y-1/ysquare

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 Question 388552: 3y+2/7ythird divide y-1/ysquareFound 2 solutions by haileytucki, Alan3354:Answer by haileytucki(390)   (Show Source): You can put this solution on YOUR website!FACTORED: 3y+(2)/(7)*y^(3){y-(1)/(y^(2)) To divide by a fraction, flip the fraction and multiply. 3y+(2)/(7(y^(3)))*(1)/(y)-(1)/(y^(2)) Multiply 7 by y^(3) to get 7y^(3). 3y+(2)/(7*y^(3))*(1)/(y)-(1)/(y^(2)) Multiply 7 by y^(3) to get 7y^(3). 3y+(2)/(7y^(3))*(1)/(y)-(1)/(y^(2)) Multiply (2)/(7y^(3)) by (1)/(y) to get (2)/(7y^(4)). 3y+(2)/(7y^(4))-(1)/(y^(2)) To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is 7y^(4). Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. 3y*(7y^(4))/(7y^(4))+(2)/(7y^(4))-(1)/(y^(2))*(7y^(2))/(7y^(2)) Complete the multiplication to produce a denominator of 7y^(4) in each expression. (21y^(5))/(7y^(4))+(2)/(7y^(4))-(7y^(2))/(7y^(4)) Combine the numerators of all expressions that have common denominators. (21y^(5)+2-7y^(2))/(7y^(4)) Reorder the polynomial 21y^(5)+2-7y^(2) alphabetically from left to right, starting with the highest order term. (21y^(5)-7y^(2)+2)/(7y^(4)) Answer by Alan3354(31518)   (Show Source): You can put this solution on YOUR website!3y+2/7ythird divide y-1/ysquare Invert the divisor and multiply by it. Cancel the y^2 = =