SOLUTION: 3y+2/7ythird divide y-1/ysquare

Question 388552: 3y+2/7ythird divide y-1/ysquare
Found 2 solutions by haileytucki, Alan3354:
Answer by haileytucki(390) (Show Source): You can put this solution on YOUR website!
FACTORED:
3y+(2)/(7)*y^(3){y-(1)/(y^(2))
To divide by a fraction, flip the fraction and multiply.
3y+(2)/(7(y^(3)))*(1)/(y)-(1)/(y^(2))
Multiply 7 by y^(3) to get 7y^(3).
3y+(2)/(7*y^(3))*(1)/(y)-(1)/(y^(2))
Multiply 7 by y^(3) to get 7y^(3).
3y+(2)/(7y^(3))*(1)/(y)-(1)/(y^(2))
Multiply (2)/(7y^(3)) by (1)/(y) to get (2)/(7y^(4)).
3y+(2)/(7y^(4))-(1)/(y^(2))
To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is 7y^(4). Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions.
3y*(7y^(4))/(7y^(4))+(2)/(7y^(4))-(1)/(y^(2))*(7y^(2))/(7y^(2))
Complete the multiplication to produce a denominator of 7y^(4) in each expression.
(21y^(5))/(7y^(4))+(2)/(7y^(4))-(7y^(2))/(7y^(4))
Combine the numerators of all expressions that have common denominators.
(21y^(5)+2-7y^(2))/(7y^(4))
Reorder the polynomial 21y^(5)+2-7y^(2) alphabetically from left to right, starting with the highest order term.
(21y^(5)-7y^(2)+2)/(7y^(4))

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
3y+2/7ythird divide y-1/ysquare
Invert the divisor and multiply by it.

Cancel the y^2
=
=

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