SOLUTION: I need help dividing (x^2+6x-50)/(x+8)

Question 387519: I need help dividing
(x^2+6x-50)/(x+8)
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
Answer should be:
(x-2) with a remainder of -34
remainder of -34 is equivalent to -34/(x+8)
answer is therefore x-2 - 34/(x+8)
the process works like this.
divide x^2 by x to get x because x*x = x^2
multiply (x+8) by x to get x^2 + 8x
subtract (x^2 + 8x) from (x^2 + 6x) to get -2x
bring down the -50 to get (-2x - 50)
divide -2x by x to get -2
multiply (x+8) by -2 to get (-2x - 16)
subtract (-2x -16) from (-2x - 50) to get -34
that's your remainder.
your answer is (x-2) with a remainder of -34
when you multiply (x-2) by (x+8) you will then need to add the remainder to get back to the original equation.
(x-2) * (x+8) = x^2 + 6x - 16
add -34 to that and you get x^2 + 6x - 50 which was your original equation.
on paper, the division will be as shown below:
***** picture not found *****

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