SOLUTION: Not sure if I'm right, please help! n^2-n-20/2n^2 * n^2+5n/n^2-25 I keep coming up with -n^2+n Am I doing this right?

Question 38364: Not sure if I'm right, please help!
n^2-n-20/2n^2 * n^2+5n/n^2-25
I keep coming up with -n^2+n
Am I doing this right?
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Let's see if you're right...from
n^2-n-20/2n^2 * n^2+5n/n^2-25 we factor and cancel where possible, so
(n - 5)(n + 4) / 2(n + 1) * n(n + 5) / (n + 5)(n - 5)
All the n+5's and n-5's cancel, so we have
n(n + 4) / 2(n + 1)
I guess you weren't right...
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