SOLUTION: (x^3+8/x^2-4)times(x^2-4x+4/x^2-2x+4) my math teacher said i got this wrong my answer was X(x-2)/-2x+4 he said you didnt solve the difference of squares correctly??

Question 382925: (x^3+8/x^2-4)times(x^2-4x+4/x^2-2x+4) my math teacher said i got this wrong my answer was X(x-2)/-2x+4 he said you didnt solve the difference of squares correctly??
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(x^3+8/x^2-4)times(x^2-4x+4/x^2-2x+4) my math teacher said i got this wrong my answer was X(x-2)/-2x+4 he said you didnt solve the difference of squares correctly??
---------------
This is a "sum" .Factor
x^3+8
= x^3+2^3
= (x+2)(x^2-x+2)
----
This is a "difference of squares":
Factor x^2-4 = (x+2)(x-2)
===============================
==============================
Your Problem:
(x^3+8/x^2-4)times(x^2-4x+4/x^2-2x+4)
-----
= [(x+2)(x^2-2x+4)/(x+2)(x-2)]
-----
Cancel the (x+2) and (x-2) and (x^2-2x+4) factors to get:
= [1*1/1*1]
= 1/(x-2)
==============
cheers,
Stan H.

Cheers,
Stan H.
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