SOLUTION: Factor completely w^2+15w+54

Algebra.Com
Question 381640: Factor completely
w^2+15w+54

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi,
factoring
w^2+15w+54
(w+9)(w+6)
Note: SUM of the inner product(9w) and the outer product(6w) = 15w
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