SOLUTION: suppose a polynomial P(x) when divided by x-9 has a quotient of 4x^3+5x^2+7x+13 and remainder 88. Find P(9)
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Question 380648: suppose a polynomial P(x) when divided by x-9 has a quotient of 4x^3+5x^2+7x+13 and remainder 88. Find P(9)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
suppose a polynomial P(x) when divided by x-9 has a quotient of 4x^3+5x^2+7x+13 and remainder 88. Find P(9)
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P(x) = (4x^3+5x^2+7x+13)+[88/(x-9)]
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P(9) = 88
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Cheers,
Stan H.
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