SOLUTION: Desperate for your help! I'm working on the squares of Binomials and had been doing really well until the last 4 questions. I understood how to write each square as a trin

Question 378958: Desperate for your help!
I'm working on the squares of Binomials and had been doing really well until the last 4 questions.
I understood how to write each square as a trinomial: (a - 9)^2 = a^2 + 18a +81
I understood how to factor: 4c^2 - 12c + 9 = (2c - 3)^2
It was when I got to these that I was lost. Completely.
8x^2 + 8x + 2
(a^2)b + 6ab^2 +9b^3
3x^8 + 48x^5 + 192x^2

Please help me by showing me a detailed step by step way to factor these types of problems!!!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
8x^2 + 8x + 2
---
Common Factor: 2
= 2(4x^2+4x+1)
= 2(2x+1)^2
---------------------------
(a^2)b + 6ab^2 +9b^3
Common Factor: b
= b(a^2+6ab+9b^2)
= b(a+3b)^2
---------------------------
3x^8 + 48x^5 + 192x^2
Common Factor: 3x^2
= 3x^2(x^6 + 16x^3 + 64)
= 3x^2(x^3+8)^2
= 3x^2(x+2)(x^2-2x+4)
============================
Cheers,
Stan H.
==============

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