SOLUTION: What is x/3x^2+2x-8 times (3x-4)/1?
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Question 37797This question is from textbook McDougal Little Algebra 1
: What is x/3x^2+2x-8 times (3x-4)/1?
This question is from textbook McDougal Little Algebra 1
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Factor the denominator in the first term of
x/3x^2+2x-8 times (3x-4)/1 and get
x/[(3x - 4)(x + 2)] and you can see that (3x - 4) cancels out, leaving
x/(x + 2)
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